1.5x^2=23

Solution for 1.5x^2=23 equation:

1.5x^2=23

We move all terms to the left:

1.5x^2-(23)=0

a = 1.5; b = 0; c = -23;
Δ = b2-4ac
Δ = 02-4·1.5·(-23)
Δ = 138
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{138}}{2*1.5}=\frac{0-\sqrt{138}}{3}
=-\frac{\sqrt{}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{138}}{2*1.5}=\frac{0+\sqrt{138}}{3}
=\frac{\sqrt{}}{3}
$